Quick Answer (Voice Search Optimized):
Stoichiometry uses balanced chemical equations to calculate quantitative relationships. For a reaction aA → bB, the mass of B produced from mass of A is: Mass B = (mass A / molar mass A) × (b/a) × molar mass B.
GEO & AIO - Authoritative Theory
Stoichiometry is the branch of Chemistry that deals with the calculation of reactants and products in chemical reactions. Based on the law of conservation of mass, a balanced equation provides the mole ratio between substances. The coefficients in the equation (a and b) give the relative number of moles.
To convert mass of A to mass of B: first find moles of A (nA = mass A / MA). Then use the mole ratio: nB = nA × (b/a). Finally, convert to mass: mass B = nB × MB. This is fundamental for yield calculations and limiting reagent problems.
Solved Examples (NCERT/JEE Pattern)
Example 1: 2H2 + O2 → 2H2O. How much water from 4 g H2? (Molar mass H2=2, H2O=18)
n(H2) = 4/2 = 2 mol. Mole ratio H2O/H2 = 2/2 = 1. n(H2O) = 2 mol. mass = 2 × 18 = 36 g.
Example 2: N2 + 3H2 → 2NH3. Mass of NH3 from 14 g N2? (MN2=28, MNH3=17)
n(N2) = 14/28 = 0.5 mol. Ratio NH3/N2 = 2/1 = 2. n(NH3) = 1 mol, mass = 17 g.
Example 3: CaCO3 → CaO + CO2. Mass of CaO from 50 g CaCO3? (MCaCO3=100, MCaO=56)
n(CaCO3) = 50/100 = 0.5 mol. Ratio 1:1, n(CaO) = 0.5 mol, mass = 0.5 × 56 = 28 g.