Specific Heat & Latent Heat Calculator Physics

Heat: Q = mcΔT or mL
Q = ---

What is the Specific Heat & Latent Heat Calculator?

Quick Answer: A tool that computes the heat required for temperature change (Q = m c ΔT) or phase change (Q = m L). Enter mass, specific heat (or latent heat) and temperature change (or select phase change). The visual shows a simple energy bar filling up to the required heat.

Theory of Heat Transfer

Specific heat capacity (c) is the heat required to raise the temperature of 1 kg of a substance by 1°C. Latent heat (L) is the heat absorbed or released during a phase change at constant temperature (fusion or vaporization). Formulas:
Q = m c ΔT for temperature changes.
Q = m L for phase changes.
Where m is mass in kg, c in J/(kg·K), ΔT in °C or K, L in J/kg. The tool can also work in calories by converting (1 cal = 4.184 J). The canvas shows a stylized thermometer or beaker filling with energy.

Step-by-Step Examples

Example 1: Heating Water

  1. Select Specific Heat. Mass=0.5 kg, c=4200 J/kg°C, ΔT=80°C. Click Calculate.
  2. Q = 0.5 * 4200 * 80 = 168,000 J (168 kJ). The bar fills to represent this energy.

Example 2: Melting Ice

  1. Switch to Latent Heat. Mass=0.5 kg, Latent Heat of fusion = 334,000 J/kg. ΔT input is hidden.
  2. Q = 0.5 * 334000 = 167,000 J. The visual indicates a phase change without temperature rise.

Example 3: Vaporizing Water

  1. Latent Heat, mass=0.5 kg, L=2,260,000 J/kg. Q = 1,130,000 J (1.13 MJ).

Frequently Asked Questions

What units are used?

Mass in kg, specific heat in J/(kg°C), latent heat in J/kg, temperature change in °C. Result Q in Joules (J). For calories, multiply J by 0.239.

Why does the temperature stay constant during a phase change?

During melting or boiling, the added energy breaks intermolecular bonds rather than increasing kinetic energy, so temperature remains constant. The latent heat accounts for this bond energy.

Can I use Celsius or Kelvin for temperature change?

Yes, ΔT is the same in Celsius and Kelvin because the size of one degree is identical.

What are typical values for specific heat?

Water: 4200 J/kg°C, Iron: 450 J/kg°C, Aluminium: 900 J/kg°C. Latent heat of fusion of ice: 334 kJ/kg, vaporization of water: 2260 kJ/kg.

Does the tool convert to calories?

The result is in Joules. You can manually convert: 1 cal = 4.184 J. A future option may include calorie output.