Understanding the Beer-Lambert Law
What is the Beer-Lambert Law?
The Beer-Lambert Law (also known as Beer's Law or the Beer-Lambert-Bouguer Law) is a fundamental relationship in spectroscopy and analytical chemistry. It states that the absorbance of a chemical species in solution is directly proportional to its concentration, the optical path length, and the molar absorptivity of the solute.
The Mathematical Formula
The primary representation of the Beer-Lambert law is:
Where the parameters are defined as:
- A = Absorbance (dimensionless quantity, representing log10(I0 / I))
- ε = Molar attenuation coefficient or molar absorptivity (expressed in L mol−1 cm−1 or M−1 cm−1)
- c = Concentration of the absorbing solute in the solution (mol/L or M)
- l = Path length of the light beam passing through the cuvette (typically 1.0 cm)
Transmittance vs. Absorbance
Transmittance (T) is the fraction of incident light that passes through the sample:
Because light absorption decreases the transmitted light exponentially, absorbance is defined logarithmically:
Thus, an absorbance of 0.0 corresponds to 100% transmittance (no light absorbed). An absorbance of 1.0 means only 10% of light is transmitted (90% absorbed), and an absorbance of 2.0 means only 1% is transmitted (99% absorbed).
Analytical Use: Calibration Curves
In research and chemical laboratories, the Beer-Lambert Law is utilized to determine unknown concentrations. By measuring the absorbance of several standards (solutions of known concentration), chemists construct a **Calibration Curve** (linear plot of Absorbance vs. Concentration). Using linear regression, the line equation is found:
Where m represents the slope (proportional to ε and l) and b is the y-intercept (stray background absorbance). Measuring the absorbance of an unknown sample then allows its concentration to be determined directly by solving for c.
Solved Examples
Problem: A solute has a molar absorptivity of 1.5 × 104 L mol−1 cm−1. Calculate the absorbance of a 2.0 × 10−5 M solution in a standard 1.0 cm cuvette.
Solution:
- Identify parameters: ε = 15,000 M−1 cm−1, c = 2.0 × 10−5 M, l = 1.0 cm.
- Apply formula: A = ε × c × l
- Substitute: A = 15000 × (2.0 × 10−5) × 1.0
- A = 0.300. (The solution has an absorbance of 0.300).
Problem: A sample shows a light transmittance of 35.0% at a specific wavelength. Determine its absorbance.
Solution:
- Given transmittance percentage T% = 35.0%.
- Apply formula: A = 2 − log10(T%)
- Substitute: A = 2 − log10(35.0)
- Calculate: A = 2 − 1.544 = 0.456.
Problem: An organic dye has an absorptivity coefficient of 8,400 M−1 cm−1. Measured in a 0.5 cm cuvette, the sample has an absorbance of 0.420. Find its concentration.
Solution:
- Given: A = 0.420, ε = 8,400, l = 0.5 cm.
- Rearrange Beer-Lambert Law: c = A / (ε × l)
- Substitute: c = 0.420 / (8400 × 0.5)
- Calculate: c = 0.420 / 4200 = 1.0 × 10−4 mol/L (or 100 μM).
Frequently Asked Questions
- Chemical interactions: Solute molecules associate, dissociate, or react with solvent, changing absorptivity.
- Refractive index changes: High concentrations alter the solution's refractive index.
- Stray light: Scattering of light by particles or inside the instrument.